Kerala PSC Previous Years Question Paper & Answer
Page:8
Below are the scanned copy of Kerala Public Service Commission (KPSC) Question Paper with answer keys of Exam Name 'HSST PHYSICS JUNIOR KHSE' And exam conducted in the year 2018. And Question paper code was '065/2018'. Medium of question paper was in Malayalam or English . Booklet Alphacode was 'A'. Answer keys are given at the bottom, but we suggest you to try answering the questions yourself and compare the key along wih to check your performance. Because we would like you to do and practice by yourself.
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The K.E. of a body is twice its rest mass energy. Find the ratio of relativistic mass to rest mass
of the body :
N =
^) ॐ (8) © 2 യ)
3
The constraint that can be expressed in the form of an equation connecting co-ordinates and
time is known as :
(ಹ) Holonomic (8) Non-holonomic
(C) Sceleronomous (D) Rhombus
De-Broglie wavelength of a particle of kinetic energy E is given by :
h 2 ಗ ह
^ न्त க (೦ ഗ് ©
The zero point energy of a linear harmonic oscillator is :
1
(ಹ) Zero छ) ग्ण © سد (D) 2೫೪
Ground state energy level of a particle in a cubical box is :
(മ) 50 fold degenerate (8) three fold degenerate
(ಲ) ہہ fold degenerate (D) non-degenerate
Momentum operator :
3 1% 9
و و 5
چوڈا )¢ الا © پچ ہج © چا മ
The degree of degeneracy for a three dimensional harmonic oscillator is :
1 1
(ക) 30+ 1)(7 + 2) 8 228+ 1)(2n+ 2)
(ಲ) (n+1)(n+2) (D) 2(n+1)(n+2)
With increase in quantum numbers, the energy difference between successive energy levels
of an anharmonic oscillator ?
(A) remains same (8) increases
(~) decreases (D) periodically increase and decrease
065/2018 8 A
