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Below are the scanned copy of Kerala Public Service Commission (KPSC) Question Paper with answer keys of Exam Name 'HSST MATHEMATICS - SR FOR SC/ST' And exam conducted in the year 2016. And Question paper code was '036/2016/OL'. Medium of question paper was in Malayalam or English . Booklet Alphacode was 'A'. Answer keys are given at the bottom, but we suggest you to try answering the questions yourself and compare the key along wih to check your performance. Because we would like you to do and practice by yourself.
D:-No general solution exists
Correct Answer:- Option-A
Question86:-Stirling's formula is the of Gauss' forward and backward formulae.
A:-Arithmetic mean
B:-Geometric mean
C:-Harmonic mean
D:-None of the above
Correct Answer:- Option-A
Question87:-The interpolating polynomial of the highest degree which corresponds the functional values “f (-1) = 9, f(0)=5,
(2) = 3,1(5) = 15 ।5
^ 3 +^ 2424145.
x*2-3x+5*
x*444x%3 +5x*245°
ലി
Correct Answer:- Option-B
Question88:-The solution of the integral equation ‘Phi (x) = x+ int_O*x (Xi -x) Phi (Xi) dXi* is
A:-‘cos x°
>
B
"0
0
0:- 5९८५४
Correct Answer:- Option-C
Question89:-The minimizing curve must satisfy a differential equation called
A:-Lagrange's equation
B:-Euler-Lagrange equation
C:-Gauss equation
D:-None of the above
Correct Answer:- Option-B
Question90:-A solid figure of revolution, for a given surface area, has maximum volume is in the case of
A:a circle
B:-a sphere
C:-an ellipse
D:-a parabola
Correct Answer:- Option-B
Question91:-A rigid body moving in space with one point fixed has degree of freedom
3ھ
8:-1
C:-6
D:-9
Correct Answer:- Option-A
Question92:-A particle of unit mass is moving under gravitational field, along the cycloid ‘x = phi - sin phi, y =1 + cos phi* .
Then the Lagrangian for motion is
A:~ phi*2 (1+cos phi) - g (1- cos phi)”
8: phi*2 (1-cos phi) + g (1+ cos phi)”
(00/72 (1-005 phi) - g (1+ cos phi)*
D:- 2phi*2 (1-cos phi) - g (1+ cos phi)*
Correct Answer:- Option-C
Question93:-°L*-1 [(1)(s (5^2+2^2))] is
A:-(1)/(a%2) (1- cos at)”
(2 sin h t)/(t)’
©: (1)/(2^2) (e* {at} -1)°
D:-*(1)/(a*2) sin h at®
Correct Answer:- Option-A
Question94:-" int_0*00 e*{-x*2}dx* is
(1/2:
(6/2)
(sqrt(pi))/(2)°
:-* «sqrt(pi)”
Correct Answer:- Option-C
Question95:-Using Fourier series, representing *x® in the interval *[-pi, pi]’, the sum of the series *1-(1)/(3) + (1)/(5) -
(1)/(7) + 0 is