Kerala PSC Previous Years Question Paper & Answer

Title : Assistant Tester cum Guager - Malabar Cements Ltd
Question Code : A

Page:19


Below are the scanned copy of Kerala Public Service Commission (KPSC) Question Paper with answer keys of Exam Name 'Assistant Tester cum Guager - Malabar Cements Ltd' And exam conducted in the year 2024. And Question paper code was '010/2024/OL'. Medium of question paper was in Malayalam or English . Booklet Alphacode was 'A'. Answer keys are given at the bottom, but we suggest you to try answering the questions yourself and compare the key along wih to check your performance. Because we would like you to do and practice by yourself.

page: 19 out of 19
Excerpt of Question Code: 010/2024/OL

B:-Entropy

C:-Free energy
D:-Internal energy
Correct Answer:- Option-B

Question98:-The difference between enthalpy and product of temperature and
entropy of a substance is

A:-G
B:-H
C:-S
D:-U
Correct Answer:- Option-A

Question99:-Std Free Energy change and equilibrium constant is related as
(a) AG° = AH? - TAS?

(0) AG° = -2.303 RT log K
(c) AG° = -RT In K
(d) AG° = -RT log K

A:-(a), (b), (c) correct
B:-(a), (b), (d) correct
C:-Only (b) and (c) correct
D:-Only equation (b) correct
Correct Answer:- Option-C

Question100:-For the reaction 3A+2B > C at 298 K, AH = 400 KJ mas, AS = 0.2 kJ
moi-.x--At what temperature will the reaction become spontaneous?

A:-Below 2000 K
B:-Below 200 K
C:-Above 2000 K
D:-Above 200 K

Correct Answer:- Option-C

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