Kerala PSC Previous Years Question Paper & Answer
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Below are the scanned copy of Kerala Public Service Commission (KPSC) Question Paper with answer keys of Exam Name 'TECHNICAL ASSISTANT DRUGS CONTROL' And exam conducted in the year 2015. And Question paper code was '124/2015'. Medium of question paper was in Malayalam or English . Booklet Alphacode was 'A'. Answer keys are given at the bottom, but we suggest you to try answering the questions yourself and compare the key along wih to check your performance. Because we would like you to do and practice by yourself.
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The condensation product of Chloroform with Acetone is :
(ക) Chloropicrin ⋅ (B) Chloretone
(0) (0110800706 (D) Chloroquine
Freon-1121is :
ல 00௬ (B) CCLF,
(©) C,CLF, (2). ೮೮1೫,
The enzyme which converts starch into maltose is :
(ക) Zymase (B) Invertase `
(€) Diastase (D) Maltase
Chlorination of benzene in presence of sunlight gives :
(A) Chloro benzene (B) Hexachloro benzene
(C) Benzyl chloride (D) Benzene hexachloride
The heat evolved when 0.50 mole HC is mixed with 0.20 mole NaOH solution will be :
(ಹ) 57.1 एव (®) 14.3 एव
ത 11.42 5 യ 114kJ
The heats of formation of COy and COyy, are — 26.4 keal/mole and — 94 keal/mole
respectively. The heat of combustion of CO will be :
(¢) +26.4 keal ര + 94 keal
(C) —67.6 keal യ - 120.4 keal
The Henderson equation for the pH of an acidic buffer solution is :
(^) ण = pKa + log [(salt)/(acid)]
(B) pH =pKa + log [(acid)/(salt)]
(0) pH =pKa - log [(salt)/(acid)]
(D) pH = pKa — log [(acid)/(salt)]
In a process AH = 100 kJ and AS = 100 J/K/mol at 400K. Then the value of AG will be :
(^) 2070 രു 100kJ
(0) 5019 D) 60kJ
124/2015 8 A
