## Kerala PSC Previous Years Question Paper & Answer

Title : ASST ENGINEER ELECTRICAL PWD/IRRIGATION/TRAVANCORE TITANIUM PRODUCTS LTD
Question Code : A

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Below are the scanned copy of Kerala Public Service Commission (KPSC) Question Paper with answer keys of Exam Name 'ASST ENGINEER ELECTRICAL PWD/IRRIGATION/TRAVANCORE TITANIUM PRODUCTS LTD' And exam conducted in the year 2014. And Question paper code was '213/2014'. Medium of question paper was in Malayalam or English . Booklet Alphacode was 'A'. Answer keys are given at the bottom, but we suggest you to try answering the questions yourself and compare the key along wih to check your performance. Because we would like you to do and practice by yourself.

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Excerpt of Question Code: 213/2014

213/2014

1.

The average power delivered to an impedance (4—j3)(2 by a current Scos (1007t = 100)A

ந்த்‌

(५) 50% (8) 4421 60 625W യു 1251

The power in a series RLC circuit will be half of that at resonance when magnitude of current
is equal to

வு च ಎ ४ AV
‏لم‎ ® 8 ^) ௯ 0

The Thevenin's equivalent of a circuit operation at w=5 rads/s, has V=371 | 159°V
and Z;=238 —j0.667 €. At this frequency, the minimal realization of the Thevenin's
impedance will have a

(வு resistor and capacitor (18) resistor, capacitor and inductor

(C) resistor and inductor (11) capacitor and inductor

If E is the electric intensity, V(V + ‏فا(‎ equal to (a) (b) :

3 © [हैं| (೧ Zero (D) Null vector

The graph of an electrical network has N nodes and B branches. The number of links L, with
respect to the choice of a tree, is given by :

(ಸ) 8-1 (0) ೫5೫ ‏مم‎ ೫-8-1 (ए) ೫-28-1

Consider a long, two-wire line composed of solid round conductors. The radius of both
conductors is .25 cm and the distance between their centres is 1 m. If this distance is doubled,
then the inductance per unit length :

(8) increases but does not double (0) halves
(C) doubles (D) decreases but does not halve

A series R - L - C circuit has R = 50 ; L = 100 pH and C = 1 pF. The lower half power
frequency of the circuit is :
(ക) 30.55 kHz (ठ) 192 kHz (C) 51.92 तवर (D) 3.05 kiz

A passive 2-port network is in a steady-state. Compared to its input, the steady state output
can never offer :

{A) higher voltage (18) lower impedance
(C) better regulation (D) greater power
3

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