Kerala PSC Previous Years Question Paper & Answer

Title : Assistant Manager (Chemical) - Kerala Ceramics Limited
Question Code : A

Page:4


Below are the scanned copy of Kerala Public Service Commission (KPSC) Question Paper with answer keys of Exam Name 'Assistant Manager (Chemical) - Kerala Ceramics Limited ' And exam conducted in the year 2022. And Question paper code was '1/2022/OL'. Medium of question paper was in Malayalam or English . Booklet Alphacode was 'A'. Answer keys are given at the bottom, but we suggest you to try answering the questions yourself and compare the key along wih to check your performance. Because we would like you to do and practice by yourself.

page: 4 out of 13
Excerpt of Question Code: 1/2022/OL

Celli) and (ii)
2:0൫ and (iv)
Correct Answer: Option-C

‘Question24:-Pick out the wrong statements from the following,

(i) Bound moisture is removed during constant rate drying period,

(i) Free moisture is removed during falling rate drying period.

(ii) The some of free moisture and equilibrium moisture in a solid is called the critical moisture,
(iv) The driving force for mass transfer in a wet solid is its free moisture content.

०0), (0) and (७)
8:00, (0) and 0)
oti id कात tiv)
Dei (0 ೫೧ರ (0)

Correct Answer: Option-D

Question25:-In a given plant, 1906 kg of Nitrogen and 475 kg of Hydrogen are fed to the synthesis reactor per hour. Production of pure ammonia from this reactor is 1633 kg/h. What is
the percent excess reactant 7


‎B:-10.5%‏
‏6
‏5:496
‎Correct Answer:- ೦೧000‏

‘Question26:-Calculate the number of moles of K.C0, in 650 ‏.و‎ Take the molecular weight ہ٢‎ K

9.3, 6

ಸಿ27 mol
8:37 mol
‏جه‎ mol
D:5.7 mol
Correct Answer: Option-C

‘Question27:-Natural gas is piped from the well at temperature 300 K and pressure 400 kPa. The gas is found to contain 90% Methane, 5.5% Ethane and the rest Nitrogen. Calculate the
partial pressure of Nitrogen.

88 كلتم
‎kPa‏ 8:26
وا جد
‎kPa‏ 0:28
‎Correct Answer:- Option-D‏
‎Question28::Which of the following statement is correct according ರ್‌‏

Pooky

D:-P = Constant
Correct Answer: Option:

Question29:-A crystallizer is charged with 100 kg of a solution containing 25% 0410, 2 in water. On cooling 10% of the original water present evaporates. Calculate the yield of
crystals when the solution is cooled to 283 K. The solubility at 283 K is 7 kg Ba(NO,),/100 kg total water.

4-20.28 kg
B-21.28 kg
19.28 kg
०-18.28 kg
Correct Answer:- ೦೧000

‘Question30::Which of the petroleum product, the Octane no 15 an important test ?


‎B:-Kerosene‏
‎೦-685/7‏

D:-Light diesel oil

Correct Answer: Option-C

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