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Below are the scanned copy of Kerala Public Service Commission (KPSC) Question Paper with answer keys of Exam Name 'Assistant Professor in Electrical and Electronics Engineering' And exam conducted in the year 2023. And Question paper code was '080/2023'. Medium of question paper was in Malayalam or English . Booklet Alphacode was 'A'. Answer keys are given at the bottom, but we suggest you to try answering the questions yourself and compare the key along wih to check your performance. Because we would like you to do and practice by yourself.
—4t 2
58. The state transition matrix of a control system is | ७ 5 6 ५ The system matrix
നം e
Ais:
-1/4 -1/8 -1/4 -1/4
(A)
७० [12 | ೨81 ೪)
-4 -8 -4 -4
©
© | | ©) ۴ हक
0 -2
59. Find the state transition matrix of A= | 1 .
‰* ९ et-e% ஓட்டு ஒப ஒட
(A) हि و हि 7 و ہہ رم ए و
൦2 -e'+20% 2௦7 ا یورام
0 21-௦3 921,494 214௦3 -‰९1 + १९०४
(© ம் डा ம் —2t ©) 1 डा 1 डा
e'-e —e'+2e 2-௦ —e' +2e
60. The state space representation of a system is given by :
x, 0 ௨ 015, 0 xy
௯1-10 0 ५५|| |+|0 |, += [1 0 01%
ಖ್ಯ ५ 0 0 || 1 X3
The system is controllable for
(0) a, #0,a, =0,a; #0 (B) a =0,a, #0, a; =0
)© يه ,0 * وه ,0 + به )0 0 ديه ,0 * وه ,0 - ره 0
61. The state space representation of a system is given by X=AX+Bu,y=CX, where
-2 4 0 ۱ ١
५ Lael | ^= [1 0]. The given system is:
೩ 1 1
(A) controllable and stable ൯) uncontrollable and stable
(C) observable and unstable (D) unobservable and unstable
62. Find all critical points of the given system and identify their nature :
|
(^) (0, 0)-saddle, (1, —1)-stable node, (-1, —1)-unstable focus
(B) (0, 0)-saddle, (1, 1)-stable node, (1, —1)-stable focus
(C) (0, 0)-stable node, (1, —1)-saddle, (-1, —1)-unstable focus
(D) (0, 0)-stable node, (1,1)-stable focus, (1,-1)-saddle
080/2023 14 A