Page:21
Below are the scanned copy of Kerala Public Service Commission (KPSC) Question Paper with answer keys of Exam Name 'Deputy Engineer (Electrical), Assistant Engineer (Electrical) - Kerala Co-operative Milk Marketing Federation Ltd, KSEB' And exam conducted in the year 2023. And Question paper code was '098/2023'. Medium of question paper was in Malayalam or English . Booklet Alphacode was 'A'. Answer keys are given at the bottom, but we suggest you to try answering the questions yourself and compare the key along wih to check your performance. Because we would like you to do and practice by yourself.
83.
84.
85.
86.
87.
88.
89.
098/23
If P and E are the average power and energy of continuous or discrete time signal,
then energy signal is
مه -ط ہمہ > ع > 0 (8 0-ط ,ره > ع > 0 رم
ಎ0 ,مه > ط > 0 )0 م دع رمه > ط > 0 (0
For a continuous time system described by y(t) = x(t/2) is
A) Causal, stable and time varying
B
0
0
)
) Linear and time-invariant
) Linear and causal
) Linear and stable
Let x(t) = cos(t) and x(t) is continuous at t = 0, then x(t) 5(t — 7) 15
A) -1 B) 0 C) cos(z) 5(t) 2) -6 (1-5)
The fundamental period of a discrete signal x[n] = 5"
A) 1/4s B) 4s C) 8s D) 1/8s
The response of LTI continuous time system to the unit step input is given by
1
3 (1 - 6731), then the impulse response of the system is
1
^) उ (1 - رم 3۷م" م٢ C) 1- اقم D) Constant
The impulse response h(t) of a LTI continuous time system is described by
h(t) = e“tu(t) + eBtu(—t) where u(t) denotes the unit step function, « and B are real
constants. This system is stable if
A) Both a and B are positive
8) Both a and f are negative
C) ais positive and B is negative
)
D) a is negative and f is positive
Consider the signal x(t) = sin (3xt) + sin (6xt), the minimum sampling interval to satisfy
the Shannon’s sampling rule is
A) 1/6s 8) 1⁄3 5 C) 12s D) 36s
-21-