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Below are the scanned copy of Kerala Public Service Commission (KPSC) Question Paper with answer keys of Exam Name ' HEAD OF SECTION COMPUTER ENGINEERING' And exam conducted in the year 2019. And Question paper code was '012/2019/OL'. Medium of question paper was in Malayalam or English . Booklet Alphacode was 'A'. Answer keys are given at the bottom, but we suggest you to try answering the questions yourself and compare the key along wih to check your performance. Because we would like you to do and practice by yourself.
A:-October 11th
B:-September 11th
C:-November 14th
D:-October 14th
Correct Answer:- Option-A
Question10:-Who was the author of ‘AUTOBIOGRAPHY OF AN INDIAN INDENTURED LABOURER’?
A:-Kalachand
B:-Munshi Rahman Khan
C:-Chota Bandhu
D:-Navin Ramgoolam
Correct Answer:- Option-B
Question11:-‘tanx+(cos x)/(1 + sin x)= ?°
Correct Answer:- Option-A
Question12:-The area of a circle of radius ‘alpha* can be found by the following integral
*4int_O*a(a*2 - x*2) dx*
int_0*2*{pi} sqrt(a*2 - x*2) 00
nt_-a“asqrt(a*2 - x*2)dx*
:-* int_O%a sqrt(a*2 - x*2)dx*
Correct Answer:- Option-C
Question13:-What is the angle between the lines * x + y = 1° and *x-y=1°
436056”
0:-` 90^@`
Correct Answer:- Option-D
Question14:-If *A = [[alpha,0],[1,1]]’ and ‘B= [[1,0],[5,1]]) then “A*2=B* for
4:-` 21018 = 4“
B:- alpha
C:-‘alpha = -1*
0:-10 ` 2101187
Correct Answer:- Option-D
Question15:-Let “A =[[4,4k,k],[0,k,4k], [0,0,4]} , if ‘det(A*2)= 16° then |k| is
A:-4
Correct Answer:- Option-B
Question16:-The constant term in the expansion of *((3x*2)/(2)- (1)/(3x))*9° , *x!=0° is
4:- ` (5)/(18)
` (7)/(18).
(5)/(17)`
:-് (7)/(17)
Correct Answer:- Option-B
Question17:-If *y = 3 In (4x*7)° , then ‘dy/dx=*
A:> (84)/(x)
(84)(x*7)°
(12)/(x*6)*
:- (21/09:
Correct Answer:- Option-D
Question18:-int_O~{(pi)/(2)} sin 4x sin 6x dx*
Correct Answer:- Option-D