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Below are the scanned copy of Kerala Public Service Commission (KPSC) Question Paper with answer keys of Exam Name 'STATISTICAL ASSISTANT GR II / STATISTICAL INVESTIGATOR GR II / COMPUTER OPERATOR GR II ' And exam conducted in the year 2018. And Question paper code was '038/2018/OL'. Medium of question paper was in Malayalam or English . Booklet Alphacode was 'A'. Answer keys are given at the bottom, but we suggest you to try answering the questions yourself and compare the key along wih to check your performance. Because we would like you to do and practice by yourself.
Correct Answer:- Option-B
Question86:-We have created a 95% confidence interval population mean for with the result (8, 13).
What conclusion will we make if we test ‘H_(0)* : population mean = 15 vs. ‘H_(1)° : population mean *!=* 15 at alpha =
0.05 ?
A:-Reject *H_(0)° in favor of 8 (1)
-Accept ‘H_(0)° in favor of *H_(1)*
C:-Fail to reject “H_(0)* in favor of *H_(1)°
D:-We cannot tell what our decision will be from the information given.
Correct Answer:- Option-A
Question87:-Given the correlation coefficient measuring the association between X and Y is 0.70, what can you say about
the coefficient of determination ?
A:-0.49
B:-0.70
C:-0.90
D:-Cannot be determined
Correct Answer:- Option-A
Question88:-According to a survey of the top 10 employers in a major city in the Midwest, a worker spends an average of
413 minutes a day on the job. Suppose the standard deviation is 25 minutes and the time spent is approximately a normal
distribution. What are the times that approximately 95.45% of all workers will fall ?
A:-[388 438]
-[338 488]
C:-[363 463]
D:-[338 438]
Correct Answer:- Option-C
Question89:-When using the normal distribution to obtain the bounds for a 99.73 percent of the values in a population, the
interval generally will be the interval obtained for the same percentage if Chebyshev's theorem is assumed
(empirical rule).
A:-Wider than
B:-Narrower than
C:-The same as
D:-Greater than or less than (depending on the size of the SD)
Correct Answer:- Option-A
Question90:-Suppose a package delivery company purchased 14 trucks at the same time. Five trucks were purchased from
manufacturer A, four from B and five from manufacturer C. The cost of maintaining each truck was recorded. The company
used ANOVA to test if the mean maintenance cost of the trucks from each manufacturer were equal. To apply the F test,
how many degrees of freedom are in the denominator ?
൧-2
8:-3
6-11
D:-14
Correct Answer:- Option-C
Question91:-The chi-square distribution can assume
A:-Only positive values
B:-Only negative values
:-Negative and positive values or zero
D:-Only zero
Correct Answer:- Option-A
Question92:-A regression equation was computed to be Y = 35 + 6X. The value of the 35 indicates that
A:-A regression line crosses the Y axis at 35
B:-The coefficient of correlation is 35
C:-The coefficient of determination is 35
D:-An increase of one unit of X will result in an increase of 35 in Y
Correct Answer:- Option-A
Question93:-Until this year the mean braking distance of a Nikton automobile moving at 60 miles per hour was 175 feet.
Nikton engineers have developed what they consider a better braking system. They test the new brake system on a random
sample of 64 cars and determine the sample mean braking distance x = 167 feet (assume the population standard
deviation is known to be 32 feet). How many cars should be tested if Nikton wants to be 95% confident of being within 1
foot of the population mean braking distance ?
A:-4194
8:4
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